Complex Numbers: Making Sense of the Square Root of −1
Understand the imaginary unit i, add, subtract, and multiply complex numbers, and simplify powers of i — with worked SAT and ACT problems.
The Short Version
- i = √−1, so i² = −1 — the one rule everything depends on.
- Complex numbers have the form a + bi (real part a, imaginary part b).
- Add/subtract by combining like terms; multiply with FOIL, then replace i² with −1.
- Powers of i cycle every four: i, −1, −i, 1. An SAT/ACT and Algebra II topic.
For a long time, "the square root of a negative number" was treated as impossible. Mathematicians fixed that by defining a new number, i, whose square is −1. That single definition opens up the complex numbers — and the good news for test-takers is that you already know how to work with them. A complex number a + bi behaves exactly like a binomial; the only new move is replacing i² with −1 whenever it appears.
This guide builds from the imaginary unit through the four operations and the cycle of powers, with worked and practice problems matched to real test difficulty at Northside Tutoring.
Why Complex Numbers Matter
Complex numbers appear on the SAT and ACT in a handful of predictable ways: simplifying powers of i, multiplying two complex numbers, and recognizing the roots of a quadratic with a negative discriminant. They're Algebra II content beyond the SSAT, but the mechanics lean entirely on skills you built in factoring and binomial multiplication.
The Imaginary Unit i
The imaginary unit is defined by one equation:
This lets you simplify the square root of any negative number: √−16 = √16 · √−1 = 4i.
The Form a + bi
Every complex number can be written as a + bi, where a is the real part and b is the imaginary part. A pure real number (like 5) is just 5 + 0i; a pure imaginary number (like 3i) is 0 + 3i.
Adding & Subtracting
Treat i like a variable and combine like terms — reals with reals, imaginaries with imaginaries:
Multiplying
Multiply complex numbers with FOIL, exactly as you would two binomials — then replace any i² with −1 and simplify:
The i² swap is the whole trick
The only thing that makes complex multiplication different from regular FOIL is that i² = −1. After distributing, hunt down every i² and turn it into −1.
Powers of i
The powers of i repeat in a cycle of four:
| Power | Value |
|---|---|
| i¹ | i |
| i² | −1 |
| i³ | −i |
| i⁴ | 1 |
After i⁴ the pattern restarts. To simplify a high power, divide the exponent by 4 and use the remainder: i²³ has remainder 3 (since 23 = 20 + 3), so i²³ = i³ = −i.
Where You'll See This — Test by Test
No reference sheet covers this. The SAT and ACT test simplifying powers of i and multiplying complex numbers. It's Algebra II material beyond the SSAT.
Digital SAT
Tests multiplying complex numbers and simplifying expressions to a + bi form.
Explore SAT Tutoring → College AdmissionsACT
Tests powers of i, basic operations, and occasionally complex roots of quadratics.
Explore ACT Tutoring → Independent School AdmissionsSSAT
Not on the SSAT — Algebra II material. Build binomial-multiplication fluency with earlier prep first.
Explore SSAT Tutoring → K-12 CurriculumAlgebra II
A core Algebra II topic and the gateway to the complex roots of polynomials.
Explore Algebra Tutoring →Watch the Lesson
Sometimes a diagram needs a voice. In the short video below, one of our Northside tutors walks through the core idea and works through test-style problems in real time.
Complex Numbers — In Plain English
A live walkthrough from our tutoring team.
— Featuring a Northside Tutoring instructor
Worked Example Problems
These problems are calibrated to the difficulty you'll actually see on test day. Try each one before opening the solution.
Simplify: (4 + 3i) + (2 − 7i).
Show solution
Combine like terms: (4 + 2) + (3 − 7)i = 6 − 4i.
Simplify: √−25.
Show solution
√−25 = √25 · √−1 = 5i.
Multiply: (2 + i)(3 − 2i).
Show solution
FOIL: 6 − 4i + 3i − 2i² = 6 − i − 2(−1) = 6 − i + 2 = 8 − i.
Simplify: i⁶.
Show solution
6 ÷ 4 leaves remainder 2, so i⁶ = i² = −1.
Simplify: (1 + i)².
Show solution
(1 + i)² = 1 + 2i + i² = 1 + 2i − 1 = 2i.
Common Mistakes to Avoid
Three traps that catch students every year
- Forgetting i² = −1. After multiplying, every i² must become −1 — this is what makes the answer come out right.
- Combining real and imaginary parts. 3 + 2i is fully simplified; you can't add a real number to an imaginary one.
- Mishandling powers of i. Use the cycle of four: divide the exponent by 4 and read the remainder.
Practice Problems — You Try
Three problems below. Work each before checking the solution.
Simplify: (5 − 2i) − (3 + 4i).
Show solution
(5 − 3) + (−2 − 4)i = 2 − 6i.
Simplify: i¹².
Show solution
12 is a multiple of 4, so i¹² = 1.
Multiply: (3 + 2i)(3 − 2i).
Show solution
This is a difference of squares: 9 − (2i)² = 9 − 4i² = 9 + 4 = 13.
The Northside Method — How We Teach This 1-on-1
Reading a blog is a great starting point. But there's a meaningful gap between understanding a concept and reflexively applying it under timed conditions. That gap is exactly what our tutors close.
Every Northside student works through a four-step framework:
- Assessment. We diagnose which specific skills are slowing your student down — not just whether they "get it" in the abstract.
- Perfect-match coach. We pair them with an elite tutor (we accept only the top 1% of applicants) whose teaching style fits how your student actually learns.
- Bespoke plan. A roadmap built around your student's target score, target timeline, and current pacing data.
- Data-driven adjustment. Every session ends with a check on whether the student's accuracy and speed are moving in the right direction.
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