
Max Pincus
Stanford University
Stanford grad, Mathematical and Computational Sciences with Economics minor. 1560 SAT, 800 Math 2. 5's on Calc AB/BC, Stats, Bio, Physics.
Test Prep · SAT
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Scholastic Aptitude Test
Northside TutoringEst. 2000
The SAT is one of the most critical elements of the college admissions process. Alongside a high school transcript, your SAT score signals to colleges how prepared you are for higher education. At Northside, we help students de-mystify the test and perform at their best on test day — whether they need a complete content review or targeted work on specific sections.
We start with a free 15-minute consultation to understand your student’s current score, target schools, and timeline — then recommend the right format and tutor match.

Cohort Leader
Max Pincus
Stanford University
Our SAT cohort sessions are small-group test prep classes that run through both Digital SAT sections — Math and Reading & Writing — with a professional tutor guiding strategy, timing, and content. Students benefit from peer learning while receiving direct feedback from the instructor.
SAT cohort prep runs fall through January, following the College Board's primary testing windows. Summer sessions may be available depending on enrollment.
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One-on-one SAT prep with an elite Northside tutor. Every session is entirely focused on your student — their diagnostic results, their target score, and their timeline.
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Stanford University
Stanford grad, Mathematical and Computational Sciences with Economics minor. 1560 SAT, 800 Math 2. 5's on Calc AB/BC, Stats, Bio, Physics.

Georgia Institute of Technology
Freshman at Georgia Tech majoring in Industrial Engineering. National Merit Finalist, AP Scholar with Distinction, and Westminster top 5%. Earned a 1540 SAT and 35 ACT. Received 5's on AP Calc BC, AP Stats, AP CSP, AP CSA, AP Chem, and AP Bio. Served as President of Mu Alpha Theta and received the Presidential Volunteer Service Award.

The University of Chicago
First-year at UChicago, Business Economics and Computer Science. AP experience in Biology, Chemistry, Stats, Calc AB/BC, English, Latin.

Georgia Institute of Technology
Westminster 2022 grad, Georgia Tech BSMS in Computer Science. 36 ACT, 1580 SAT. National Merit Scholar.
SAT FAQ
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35 Hard SAT Math Questions
Compiled by our tutors from real Algebra and Advanced Math questions at the hardest difficulty level tested on the SAT. Attempt each one, then reveal the answer and a full explanation.
Correct Answer: 403
For a linear equation in one variable to have infinitely many solutions, the coefficients of x must be equal on both sides, and the constant terms must also be equal. Rewriting the left side gives 3x + 7 − s13 = rx − 8r. Matching x-coefficients gives r = 3. Matching constants gives 7 − s13 = −8(3) = −24, so s13 = 31, and s = 403.
Correct Answer: 33
The slope between the two given points is −15 − 13(k + 7) − k = −287 = −4. Using the point (k, 13) and the y-intercept (k − 5, b): −4 = 13 − b5. Multiplying both sides by 5 gives −20 = 13 − b, so b = 33.
Correct Answer: A
Rewriting ax + ky = 6 in slope-intercept form gives y = −akx + 6k. The point (0, −3) is the y-intercept, so 6k = −3. Multiplying both sides by k gives 6 = −3k, so k = −2.
Correct Answer: D
In 5 hours the auger removed 24,000 − 19,350 = 4,650 bushels, a rate of 4,6505 = 930 bushels per hour. Solving 24,000 − 930x = 12,840 gives x = 12.
Correct Answer: D
Multiplying the first equation by −2 gives −2ax − 2by = −144. Adding this to the second equation gives (−2a + 6)x = −88. Since x = 4 at the intersection, (−2a + 6)(4) = −88, so −2a + 6 = −22, giving a = 14.
Correct Answer: D
The cost is $270 for the first day plus $135 for each of the remaining (x − 1) days: y = 270 + 135(x − 1), which simplifies to y = 135x + 135.
Correct Answer: D
Taking the bus takes w + 5 minutes in total (wait time plus the ride). Walking is faster exactly when w + 5 > 20.
Correct Answer: 2/7 (also accepted: .2857, 0.285, 0.286)
Multiplying the first equation by 354 gives 72x + 494y = 52, which matches the second equation, so g = 72 and k = 494. Therefore gk = 7/249/4 = 27.
Correct Answer: D
Dividing the second equation by 4 gives 7x + 6y = 5 — identical to the first equation, so any point that satisfies one satisfies both. Substituting r for y and solving for x gives x = −6r7 + 57, so the point is (−6r7 + 57, r).
Correct Answer: D
Distributing and simplifying gives (r − 28)x = 23. For the equation to have exactly one solution, the coefficient (r − 28) cannot equal 0 — so r cannot equal 28.
Correct Answer: D
At $4 per gallon and 25 miles per gallon, the cost per mile is 425 dollars. Reducing weekly spending by $5 means 425m = 5.
Correct Answer: A
An increase of 9.10 kelvins increases F(x) by 95(9.10) = 16.38 degrees Fahrenheit.
Correct Answer: B
The first session is free ($0), the second is half off ($12.70), and the remaining (x − 2) sessions are full price: f(x) = 0 + 12.70 + 25.40(x − 2), or f(x) = 25.40(x − 2) + 12.70.
Correct Answer: D
Setting F(x) = 2.74 gives 0 = −0.19(x − 3), so x = 3 — which is December 1, 2014 (3 months after September 1). So 2.74 is the average price per gallon on that date.
Correct Answer: D
Staining twice covers 2w square feet. Dividing by 170 square feet per gallon gives 2w170, which simplifies to w85.
Correct Answer: C
The triangle inequality gives three conditions: 6 + x > 12, 6 + 12 > x, and 12 + x > 6. Together, these simplify to 6 < x < 18.
Correct Answer: 2/43 (also accepted: .0465, 0.046, 0.047)
Since f(cx) = x − 8 for all x, setting cx = 2 gives x = 2c. Substituting into f(2) = 35: 2c − 8 = 35, so 2c = 43, and c = 243.
Correct Answer: 20
The condition is 6n500 ≤ 0.25, so 6n ≤ 125, which gives n ≤ 20.833. Since n must be a whole number, the greatest possible value is 20.
Correct Answer: 609
Since a < 0, |a|a = −1. Then g(15a) = 15(−1) − 14 = −29, and g(7a) = 7(−1) − 14 = −21. The product of g(15a) and g(7a) is (−29)(−21) = 609.
Correct Answer: 20
Substituting x = 0, y = −757 into y = −ax + b − 12 gives −757 = −1 + b − 12, so b = 167. Since ab = 3207, a = 320/716/7 = 20.
Correct Answer: 27
Combining the right-hand side over the common denominator x(x + 51) gives (p + w)x + 51px(x + 51). Matching numerators with 29x + 102 gives p + w = 29 and 51p = 102 (so p = 2). Therefore w = 29 − 2 = 27.
Correct Answer: D
Since f(−9) = f(3), the vertex's x-coordinate is halfway between −9 and 3, so h = −3. Writing f in vertex form and matching to ax² + 4x + c shows a = 23, so a ≥ 1 is false (II is not true). It also shows k = c − 6; since k < 0 just means c < 6, c could still be zero or positive, so c < 0 is not necessarily true (I is not true either). Neither statement must be true.
Correct Answer: A
The population increases by 4% each time the exponent 64t increases by 1 — that is, each time t increases by 23 of a year. Since 23 of a year is 8 months, n = 8.
Correct Answer: D
Substituting x = −5 into x² + y² = 36 gives y² = 11, and since y < 0, y = −√11. Substituting x = −5 and y = −√11 into the second equation: −√11 = −5m + b4. Adding 5m to both sides and multiplying by 4 gives b = 20m − 4√11.
Correct Answer: A
Since the graph passes through (0, 22), g(0) = −a−b = 22, so a = 22b. Since g(−22) = 0, the numerator must be 0: (−22)² − (−22) − 22b = 0, or 484 + 22 = 22b, so 22 + 1 = b (after dividing by 22), giving b = 23.
Correct Answer: A
For x² − cx − b to equal x + b, x² − c must factor as (x + b)(x − b) = x² − b² — a difference of squares. So c must be a perfect square; only choice A (4) is one.
Correct Answer: A
The left side factors as (x + b)(57x + a) = 0, giving solutions x = −b and x = −a57. Their product is ab57. Since this equals kab, k = 157.
Correct Answer: 15.5 (also accepted: 31/2)
Expanding (3x² + a)(2x² + b) and matching coefficients gives 3b + 2a = 31 and ab = 35, whose positive-integer solution is a = 5, b = 7. Repeating the same relationships while allowing noninteger constants gives c = 10.5, d = 35/10.5. So a + c = 5 + 10.5 = 15.5.
Correct Answer: 31
Completing the square on each equation gives r = −3 − √2, s = −3 + √2, t = −4 − 2√2, u = −4 + 2√2. Then r + t = −7 − 3√2 and s + u = −7 + 3√2. Since c equals the product of the new roots, c = (−7)² − (3√2)² = 49 − 18 = 31.
Correct Answer: B
A population that is 150% more each year is multiplied by 1 + 1.5 = 2.5 annually, so n = a(2.5)ᵗ for some initial value a. Since n = 180 when t = 1, 180 = 2.5a, so a = 72. The model is n = 72(2.5)ᵗ.
Correct Answer: D
Each choice can be written as (3x)(x) + (7)(2b) terms, so factoring as (3x + 7)(x + 2b) gives 3x² + (7 + 6b)x + 14b. Testing each choice's x-coefficient (7, 28, 42, 49) for a positive-integer b shows only 49 works, where 7 + 6b = 49 gives b = 7.
Correct Answer: B
Multiplying every term by the common denominator 12xyz and simplifying gives y² = 4x − 3z12x²z². Since y is positive, y = √4x − 3z12x²z².
Correct Answer: D
Expanding (hx + k)(x + j) and matching the constant term gives kj = −45. Since h, k, j are integers, j = −45k must be an integer — so 45k must be an integer too.
Correct Answer: 41/81 (also accepted: .5061, .5062, 0.506)
The left side is equivalent to p2/3, so p2/3 = t9/7. Substituting t = p3n−1 gives p2/3 = p(9/7)(3n−1), so 23 = 97(3n − 1). Multiplying both sides by 21 gives 14 = 27(3n − 1), or 14 = 81n − 27. Adding 27 and dividing by 81 gives n = 4181.
Correct Answer: D
Writing the parabola as y = a(x − 9)² − 14 and expanding shows a + b + c = 64a − 14. Since the vertex is below the x-axis and the parabola crosses it twice, the parabola must open upward, so a > 0. Only choice D (−12) gives a positive a (a = 132).

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