Stoichiometry & the Mole: Counting Atoms by Weighing Them
Understand the mole, molar mass, and stoichiometry — using balanced equations and mole ratios to relate amounts of reactants and products — the chemistry background for ACT Science.
The Short Version
- A mole is a fixed count of particles: 6.02 × 10²³ (Avogadro's number).
- Molar mass (grams per mole) comes from the periodic table; it converts grams ↔ moles.
- A chemical equation must be balanced — the same atoms on both sides.
- The coefficients give mole ratios that relate reactants and products. ACT Science / chemistry background.
You can't count atoms one by one — a speck of matter holds trillions upon trillions. So chemists use the mole, a counting unit like a "dozen" but vastly larger, to handle atoms in practical amounts. Combined with a balanced chemical equation, the mole lets you do something powerful: predict exactly how much product a reaction will yield from a given amount of reactant. That predictive bookkeeping is stoichiometry.
This guide builds from the mole through balanced equations and mole ratios, with worked and practice questions matched to the level seen in ACT Science and chemistry at Northside Tutoring.
Why Stoichiometry Matters
Stoichiometry is the quantitative heart of chemistry and appears in ACT Science chemistry passages, often as a calculation or a proportion. The reasoning is really applied ratios. (The SAT has no science section.)
The Mole: A Chemist's Dozen
A mole is simply a count: one mole is 6.02 × 10²³ particles (Avogadro's number). Just as "a dozen" always means 12, "a mole" always means that many atoms or molecules. It's the bridge between the atomic scale and amounts we can weigh.
Molar Mass
The molar mass of a substance is its mass in grams per mole, and it's read straight off the periodic table: an element's atomic mass in grams is one mole of it. Carbon's atomic mass is about 12, so one mole of carbon weighs about 12 grams. Molar mass converts between grams and moles:
Balancing Equations
Matter is conserved, so a chemical equation must have the same number of each atom on both sides. You balance by adjusting the coefficients (the numbers in front), never the subscripts. For example:
Now there are 4 hydrogen and 2 oxygen atoms on each side — balanced.
Mole Ratios
Once balanced, the coefficients give you mole ratios — the recipe for the reaction. In 2H₂ + O₂ → 2H₂O, the ratio of hydrogen to water is 2:2 (or 1:1), and oxygen to water is 1:2. These ratios let you convert moles of one substance into moles of another.
Coefficients are the recipe
Think of a balanced equation like a recipe: "2 cups H₂ plus 1 cup O₂ makes 2 cups H₂O." The coefficients tell you the proportions, and stoichiometry just scales the recipe up or down.
A Stoichiometry Strategy
- Balance the equation.
- Convert the given amount to moles (grams ÷ molar mass).
- Use the mole ratio from the coefficients to find moles of the target.
- Convert back to grams if needed (moles × molar mass).
Where You'll See This — Test by Test
Stoichiometry supports ACT Science chemistry passages; the SAT has no science section and the SSAT doesn't test it. It's core high-school and AP Chemistry.
ACT Science
Chemistry passages on the ACT Science section may involve mole reasoning and reading reaction data.
Explore ACT Tutoring → K-12 CurriculumChemistry
The mole and stoichiometry are central to high-school and AP Chemistry.
Explore Science Tutoring → College AdmissionsSAT
No SAT science section; chemistry isn't tested there among admissions exams.
Explore SAT Tutoring → K-12 CurriculumSchool Science
Applied proportional reasoning at the heart of chemistry.
Explore Science Tutoring →Watch the Lesson
Sometimes a diagram needs a voice. In the short video below, one of our Northside tutors walks through the core idea and works through test-style problems in real time.
The Mole & Stoichiometry — In Plain English
A live walkthrough from our tutoring team.
— Featuring a Northside Tutoring instructor
Worked Example Problems
These problems are calibrated to the difficulty you'll actually see on test day. Try each one before opening the solution.
How many particles are in one mole?
Show solution
6.02 × 10²³ (Avogadro's number).
Carbon has a molar mass of 12 g/mol. How many moles are in 36 g of carbon?
Show solution
moles = grams ÷ molar mass = 36 ÷ 12 = 3 moles.
Balance: H₂ + O₂ → H₂O.
Show solution
2H₂ + O₂ → 2H₂O — 4 H and 2 O on each side.
In 2H₂ + O₂ → 2H₂O, how many moles of water form from 4 moles of H₂?
Show solution
The H₂:H₂O ratio is 2:2 (1:1), so 4 moles H₂ → 4 moles H₂O.
When balancing, may you change subscripts?
Show solution
No — only change the coefficients. Changing subscripts changes the substance itself.
Common Mistakes to Avoid
Three points students often miss
- Changing subscripts to balance. Only adjust coefficients — changing a subscript changes the compound.
- Skipping the balance step. Mole ratios come from the balanced coefficients; an unbalanced equation gives wrong ratios.
- Forgetting to convert grams to moles. Stoichiometry works in moles — convert with molar mass first.
Practice Problems — You Try
Three problems below. Work each before checking the solution.
How many moles are in 40 g of a substance with molar mass 20 g/mol?
Show solution
40 ÷ 20 = 2 moles.
Balance: N₂ + H₂ → NH₃.
Show solution
N₂ + 3H₂ → 2NH₃ (2 N and 6 H on each side).
In N₂ + 3H₂ → 2NH₃, how many moles of NH₃ form from 6 moles of H₂?
Show solution
The H₂:NH₃ ratio is 3:2. So 6 moles H₂ × (2/3) = 4 moles NH₃.
The Northside Method — How We Teach This 1-on-1
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