Inequalities & Absolute Value: When the Answer Is a Range
An equation has an answer; an inequality has a whole range of them. Solve inequalities exactly like equations — with one famous exception — and treat absolute value as a question about distance, and these problems become routine.
The Short Version
- Solve an inequality like an equation — isolate the variable step by step.
- The one exception: when you multiply or divide by a negative, flip the inequality sign.
- Absolute value |x| is distance from zero, so |x| = 5 has two answers: x = 5 and x = −5.
- |x| < a means −a < x < a ("between"); |x| > a means x < −a or x > a ("outside") — a classic SAT/ACT distinction.
Most of algebra asks "what value makes this true?" Inequalities ask a richer question: "what range of values makes this true?" The mechanics are almost identical to solving equations, which is good news. There's just one rule that's unique to inequalities, and one idea — absolute value as distance — that turns the trickier problems into two simple ones.
This guide covers linear and compound inequalities, the flip rule everyone forgets, and the full absolute-value toolkit, with worked and practice problems matched to real test difficulty at Northside Tutoring.
Why These Matter
Inequalities model real constraints: budgets, minimum scores, maximum capacities. The tests use them in word problems ("at least," "no more than," "fewer than") and in pure-algebra solve-the-range questions. Absolute value adds a layer the SAT and ACT love because it quietly hides two cases inside one expression.
Solving Linear Inequalities
Treat the inequality sign just like an equals sign: do the same operation to both sides until the variable is alone. To solve 3x + 4 < 19, subtract 4 (3x < 15) and divide by 3 (x < 5). Done.
The Flip Rule
Here is the only rule that's different from equations: whenever you multiply or divide both sides by a negative number, reverse the inequality sign.
Dividing by −2 flips < into >. Skipping this flip is the single most common inequality error on every test.
Why the flip happens
Numbers reverse order when negated: 2 < 3, but −2 > −3. Multiplying an inequality by a negative reflects every value across zero, which reverses the direction of the comparison.
Compound Inequalities
A compound inequality squeezes a variable between two bounds, like −3 < 2x + 1 ≤ 7. Solve it by doing the same operation to all three parts at once: subtract 1 (−4 < 2x ≤ 6), then divide by 2 (−2 < x ≤ 3).
Absolute Value: Distance From Zero
The absolute value |x| is the distance of x from zero on the number line, so it's never negative. Because two points sit a given distance from zero, an absolute-value equation usually has two solutions:
To solve |2x − 1| = 9, split into two equations: 2x − 1 = 9 (x = 5) and 2x − 1 = −9 (x = −4).
Absolute-Value Inequalities
This is where students slip. The direction of the inequality changes the shape of the answer:
| Form | Becomes | In words |
|---|---|---|
| |x| < a | −a < x < a | between ("and") |
| |x| > a | x < −a or x > a | outside ("or") |
Memory aid: less thand (< gives an "and" / between answer) and greator (> gives an "or" / outside answer).
Where You'll See This — Test by Test
Inequalities and absolute value are pure algebra — nothing on a reference sheet. The SAT and ACT both test the flip rule and the two shapes of absolute-value inequalities; the SSAT Upper Level keeps to basic linear inequalities.
Digital SAT
Common, including systems of inequalities and "which value satisfies" questions. The flip rule and number-line ranges show up often.
Explore SAT Tutoring → College AdmissionsACT
Tests linear and absolute-value inequalities, plus the between/outside distinction. Watch the sign flip.
Explore ACT Tutoring → Independent School AdmissionsSSAT
Upper Level covers solving and graphing basic one-variable inequalities on a number line.
Explore SSAT Tutoring → K-12 CurriculumSchool Algebra
A core Algebra I topic; absolute-value functions return in Algebra II graphing.
Explore Algebra Tutoring →Watch the Lesson
Sometimes a diagram needs a voice. In the short video below, one of our Northside tutors walks through the core idea and works through test-style problems in real time.
Inequalities & Absolute Value — In Plain English
A live walkthrough from our tutoring team.
— Featuring a Northside Tutoring instructor
For the developer / editor
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Worked Example Problems
These problems are calibrated to the difficulty you'll actually see on test day. Try each one before opening the solution.
Solve: 5x − 3 ≥ 17.
Show solution
Add 3: 5x ≥ 20. Divide by 5: x ≥ 4.
Solve: −4x + 1 > 13.
Show solution
Subtract 1: −4x > 12. Divide by −4 and flip the sign: x < −3.
Solve the compound inequality: 1 ≤ x + 4 < 9.
Show solution
Subtract 4 from all three parts: −3 ≤ x < 5.
Solve: |x − 2| = 6.
Show solution
Split into two cases: x − 2 = 6 → x = 8; and x − 2 = −6 → x = −4.
Solve: |x + 1| < 5.
Show solution
"Less than" gives a between answer: −5 < x + 1 < 5.
Subtract 1: −6 < x < 4.
Common Mistakes to Avoid
Three traps that catch students every year
- Forgetting to flip the sign. Multiplying or dividing by a negative reverses the inequality. This is the most-missed step in all of inequality algebra.
- Giving one answer to an absolute-value equation. |x| = 7 has two solutions. Always split into the positive and negative cases.
- Mixing up the two inequality shapes. |x| < a is "between" (and); |x| > a is "outside" (or). Don't write a between-answer for a greater-than problem.
Practice Problems — You Try
Three problems below. Work each before checking the solution.
Solve: 2x + 7 ≤ 1.
Show solution
Subtract 7: 2x ≤ −6. Divide by 2: x ≤ −3.
Solve: −3x ≥ 12.
Show solution
Divide by −3 and flip: x ≤ −4.
Solve: |2x − 3| > 7.
Show solution
"Greater than" gives an outside answer: 2x − 3 > 7 or 2x − 3 < −7.
First: 2x > 10 → x > 5. Second: 2x < −4 → x < −2.
The Northside Method — How We Teach This 1-on-1
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